I think 0 has to always be in the set of digits because any number X can be written 0X, e.g. 1 = 01. See the derivation in the comment you replied to 😁
I don’t know if it has a base designation, but there is a way to represent natural numbers without 0. You just use 1, and numbers are distinguished by the number of 1s. So you’d count 1 11 111 1111 11111 and so on.
I think you’re thinking of the unary numeral system. While some people do call it “base 1”, it’s not really a positional number system like the other base N systems. In unary, you “write” 0 by just not writing anything.
I think it would also be {1,0}, because π = … + 0×π2 + 1×π + 0×1 + 0×π^(-1) + … = (…00010.000…)_π, right?
If your only digit is pi, I believe it’s {1}
I think 0 has to always be in the set of digits because any number X can be written 0X, e.g. 1 = 01. See the derivation in the comment you replied to 😁
I don’t know if it has a base designation, but there is a way to represent natural numbers without 0. You just use 1, and numbers are distinguished by the number of 1s. So you’d count 1 11 111 1111 11111 and so on.
I think you’re thinking of the unary numeral system. While some people do call it “base 1”, it’s not really a positional number system like the other base N systems. In unary, you “write” 0 by just not writing anything.